x^2-8x+14=x-

Solution for x^2-8x+14=x- equation:

x^2-8x+14=x-

We move all terms to the left:

x^2-8x+14-(x-)=0

We add all the numbers together, and all the variables

x^2-8x-(+x)+14=0

We get rid of parentheses

x^2-8x-x+14=0

We add all the numbers together, and all the variables

x^2-9x+14=0

a = 1; b = -9; c = +14;
Δ = b2-4ac
Δ = -92-4·1·14
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-5}{2*1}=\frac{4}{2}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+5}{2*1}=\frac{14}{2}
=7
$